A) \[V{{N}^{1/3}}\]
B) \[V{{N}^{2/3}}\]
C) \[V\]
D) \[VN\]
Correct Answer: B
Solution :
Key Idea: Volume of \[N\] small drops is equal to volume of single big drop. Volume of \[N\] small drops = volume of one big drop \[i.e.,\] \[\left( \frac{4}{3}\pi {{r}^{3}} \right)N=\frac{4}{3}\pi {{R}^{3}}\] \[\Rightarrow \] \[R={{N}^{1/3}}r\] \[V'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Nq}{R}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Nq}{{{N}^{1/3}}r}\] \[\Rightarrow \] \[V'={{N}^{2/3}}V\] \[\left( as\,\,V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r} \right)\]
You need to login to perform this action.
You will be redirected in
3 sec
