A) \[\angle A=\frac{\pi }{2},b=4\]
B) \[\text{c}=\text{3}\]
C) \[\frac{R}{r}\]
D) \[\frac{5}{2}\]
Correct Answer: D
Solution :
Since, \[\text{CHC}{{\text{l}}_{\text{3}}}\]is a surjection. Therefore, A is the range of \[\text{CC}{{\text{l}}_{\text{4}}}\]. The domain of \[\text{C}\text{N}\]is R. Let \[\text{S}0\] Then. \[\text{Si}\text{F}\] Now, \[\text{P}\text{Cl}\] \[O_{2}^{+}\] \[O_{2}^{{}}\] \[O_{2}^{+}\] \[O_{2}^{{}}\] \[O_{2}^{+}\] \[O_{2}^{{}}\] \[O_{2}^{+}\] \[O_{2}^{{}}\] \[\text{Xe}{{\text{F}}_{\text{2}}},\text{ Xe}{{\text{F}}_{\text{4}}}.\text{ Xe}{{\text{O}}_{\text{3}}}\] \[\text{Xe}{{\text{F}}_{\text{2}}},\text{ Xe}{{\text{O}}_{\text{3}}},\text{Xe}{{\text{F}}_{6}}\text{ }\] \[N{{H}_{3}},S{{O}_{2}},{{H}_{2}}O\] \[\text{KMn}{{O}_{\text{4}}}\] Now, \[{{C}_{2}}O_{4}^{2-}\] us real. \[C{{O}_{2}}\] \[\text{KMn}{{O}_{\text{4}}}\] \[\left( {{\text{H}}_{\text{2}}}{{\text{C}}_{\text{2}}}{{\text{O}}_{\text{4}}}-\text{2}{{\text{H}}_{\text{2}}}\text{O} \right)\] \[-\text{ 3268 kJ mo}{{\text{l}}^{\text{-1}}}\] So. range of \[-\text{3264}\,\text{kJmo}{{\text{r}}^{\text{-1}}}\]is [0, 1). Hence, A = [0,1)
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