question_answer

The orthocentre of the triangle formed by (0,0), (8, 0) and (4, 6) is

A) \[f\]      

B) \[1.27f\]

C) \[\text{1}.0\text{1}\times \text{1}{{0}^{\text{5}}}\text{ N}/{{\text{m}}^{\text{2}}}\]                    

D) \[\text{9}.\text{13}\times \text{1}{{0}^{\text{4}}}\text{ N}/{{\text{m}}^{\text{2}}}\]

Correct Answer: A

Solution :

                Line perpendicular to OA passing through B is \[x=4\]. Slope of \[AB=-\frac{3}{2}\] Line perpendicular to AB and passes through origin is                 \[y=\frac{2}{3}x\] \[\therefore \]The point of intersection of a line x = 4 and \[y=\frac{2}{3}x\]is\[\left( 4,\frac{8}{3} \right)\], which is the required orthocentre.