A) \[\therefore \]
B) \[\left( \frac{-3-{{y}_{1}}}{4-{{x}_{1}}} \right)(1)=-1\]
C) \[\Rightarrow \]
D) \[{{y}_{1}}+{{x}_{1}}=1\]
Correct Answer: D
Solution :
Given, \[\frac{3}{2}M{{L}^{2}}\] \[\frac{3}{4}M{{L}^{2}}\] \[M{{L}^{2}}\] This complex number lies in IV quadrant. When we rotate this point in 180° clockwise, then this point moves in II quadrant. So, new complex number will be \[{{R}_{1}}\] \[{{R}_{2}}\]Required complex number is \[{{Q}_{1}}\] i.e., \[{{Q}_{2}}\]
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