A) -2
B) -1
C) 0
D) \[s=\frac{{{t}^{2}}}{4}\]
Correct Answer: D
Solution :
Given, \[\mu \] To satisfy Rolle's theorem, it should be continuous in [0,1] i.e., \[W\] \[\frac{4W}{3}\] \[\frac{5W}{2}\] \[\frac{\pi }{2}\] \[\sigma =\text{5}.\text{67}\times \text{1}{{0}^{-\text{8}}}\text{W}-{{\text{m}}^{\text{2}}}{{\text{K}}^{\text{-4}}}\] (using L? Hospital?s rule) \[y=5\sin \frac{\pi x}{3}\cos 40\pi t\] \[t\] \[{{(Kg)}^{1/2}}\] \[{{(Kg)}^{-1/2}}\]which shows a > 0, otherwise it would be discontinuous. When \[{{(Kg)}^{2}}\]is differentiable in (0, 1) and \[{{(Kg)}^{-2}}\]. Hence, \[\frac{pV}{nT}\] is the possible answer.
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