A) no maxima and minima
B) one maximum and one minimum
C) two maxima
D) two minima
Correct Answer: B
Solution :
Given, \[{{P}_{2}}\] On differentiating w.r.t.\[{{P}_{1}}\], we get \[{{P}_{2}}\] For maxima or minima, put \[\text{2}\times \text{1}{{0}^{\text{7}}}\text{m}/\text{s}\] \[\text{2}\times \text{1}{{0}^{-2}}T\] \[\left( \frac{e}{m} \right)\] \[\text{1}.\text{76}\times \text{1}{{0}^{\text{11}}}\text{C}/\text{kg}\] \[2B\] \[\frac{B}{4}\] \[\frac{B}{2}\] Now, \[y=A\sin (Bx+Ct+D)\] At \[[{{m}^{0}}{{L}^{-1}}{{T}^{0}}]\] \[[{{m}^{0}}{{L}^{0}}{{T}^{-1}}]\] At \[[{{m}^{0}}{{L}^{-1}}{{T}^{-2}}]\] \[[{{m}^{0}}{{L}^{0}}{{T}^{0}}]\] Hence, \[1.5\mu \] has one maximum and one minimum.
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