JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2014

  • question_answer
    If\[\text{3}.\text{18}\times \text{1}{{0}^{8}}m/s\] and \[\text{3}.\text{33}\times {{10}^{\text{8}}}\text{ m}/\text{s}\] then \[\theta =\text{45}{}^\circ \] is equal to

    A)  \[\frac{-y}{x}\]                                

    B) \[\frac{y}{x}\]    

    C) \[-\frac{x}{y}\]                                 

    D) \[\frac{x}{y}\]

    Correct Answer: C

    Solution :

                    Given,\[\frac{2}{3}\text{m}/\text{s}\]and \[{{\lambda }_{0}},\] Put \[\frac{25}{16}{{\lambda }_{0}}\] \[\frac{27}{20}{{\lambda }_{0}}\]\[\frac{20}{27}{{\lambda }_{0}}\]and \[\frac{16}{25}{{\lambda }_{0}}\] \[3\Omega \]\[4\Omega \] and \[4.5\Omega \] On differentiating w.r.t. \[5\Omega \], we get \[\frac{\sqrt{3}}{1}\]and \[\frac{(\sqrt{3}+1)}{(\sqrt{3}-1)}\] \[\frac{(\sqrt{3}+1)}{1}\]              \[\frac{4}{3}\]


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