A) \[1\mu V\]
B) \[\text{1}.\text{96}\times \text{1}{{0}^{-\text{8}}}\text{ m}/\text{s}\]
C) \[{{(\tan x)}^{\sin x}}[\sec x+\cos x\log \tan x]\]
D) None of the above
Correct Answer: C
Solution :
Given, \[\text{ }\!\!\beta\!\!\text{ }\] On taking log both sides, we get \[\left( \frac{1}{V(volume)} \right)\] On differentiating w.r.t. x we get \[\frac{3}{4}\text{m}/\text{s}\] \[\Rightarrow \]\[\frac{1}{3}\text{m}/\text{s}\] \[\frac{3}{2}\text{m}/\text{s}\]
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