A) 2.25 m
B) 15 m
C) 10 m
D) 5m
Correct Answer: B
Solution :
In order to climb a height -h the boy utilizes potential energy \[=mgh\] Also \[{{R}_{2}}\] Energy of one bread \[{{Q}_{1}}\] Efficiency of boy = 28% Hence, energy consumed by boy is \[{{Q}_{2}}\] \[{{Q}_{1}}{{R}_{2}}\ne {{Q}_{2}}{{R}_{1}}\] From law of conservation of energy, this energy is utilised in giving potential energy \[{{Q}_{1}}{{R}_{2}}={{Q}_{2}}{{R}_{1}}\]where, g is acceleration due to gravity. \[s=\frac{{{t}^{2}}}{4}\] \[T\propto V\]
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