A) \[30{}^\circ \]
B) \[60{}^\circ \]
C) \[90{}^\circ \]
D) None of these
Correct Answer: C
Solution :
Given.\[{{\sin }^{-1}}\left( \frac{9}{8} \right)\] \[{{45}^{o}}\]\[{{60}^{o}}\] \[{{\sin }^{-1}}\left( \frac{8}{9} \right)\] \[\beta =0.\text{1}\] \[{{P}_{1}}\] \[{{P}_{2}}\] \[{{P}_{1}}\] \[{{P}_{2}}\] \[\text{2}\times \text{1}{{0}^{\text{7}}}\text{m}/\text{s}\] \[\text{2}\times \text{1}{{0}^{-2}}T\] \[\left( \frac{e}{m} \right)\] Hence, ABC is a right angled triangle at A \[\text{1}.\text{76}\times \text{1}{{0}^{\text{11}}}\text{C}/\text{kg}\] \[2B\]
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