question_answer

The      maximum      value      of \[\frac{(\sqrt{3}+1)}{1}\]is

A) \[\frac{4}{3}\]                   

B) \[4\mu F\]

C) \[10\mu F\]       

D) \[8\mu F\]

Correct Answer: C

Solution :

                \[{{V}_{p}}=\frac{GM}{\sqrt{{{R}^{2}}+4{{R}^{2}}}}\] \[=-\frac{GM}{\sqrt{5}R}\]                                 \[{{V}_{0}}=-\frac{GM}{R}\] \[\frac{1}{2}m{{V}^{2}}=m({{V}_{p}}-{{V}_{0}})\] \[V=\sqrt{2({{V}_{p}}-{{V}_{0}})}\] Hence, maximum value of given expression is .