A) (3,-5,-3)
B) (4,-7.-9)
C) (0,2,-1)
D) (-3,5,3)
Correct Answer: B
Solution :
Given equation of line is \[=3\min 56=4\min \](say) Now,\[T=\frac{KV}{\sum as}\] \[T\propto V\] DC's of the given line are\[l=\frac{M}{V}=\frac{M}{mass/density}\]. Any point on the line is \[Mass=1g={{10}^{3}}kg\] But it is given, \[Density=5g/c{{m}^{2}}\] \[=\frac{5\times {{10}^{3}}}{{{({{10}^{-2}})}^{3}}}=5\times {{10}^{3}}\] Points are \[l=\frac{6\times {{10}^{-7}}\times 5\times {{10}^{3}}}{{{10}^{-3}}}=3A/m\] and\[{{V}_{p}}=\frac{GM}{\sqrt{{{R}^{2}}+r}}\].
You need to login to perform this action.
You will be redirected in
3 sec
