JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2014

  • question_answer
    If\[\left[ {{\text{F}}^{2}}\text{L}{{\text{T}}^{\text{-2}}} \right]\]and \[-\text{273}.\text{15}{}^\circ \text{F}\]then \[-\text{453}.\text{15}{}^\circ \text{F}\] is equal to

    A) \[-\text{459}.\text{67}{}^\circ \text{F}\]              

    B)  \[-\text{491}.\text{67}{}^\circ \text{F}\]

    C)     \[\text{52}00\text{{ }\!\!\mathrm{\AA}\!\!\text{ }}\]                                

    D)  \[\text{Vc}=\text{1}.\text{5V}\]

    Correct Answer: A

    Solution :

                    Given. \[\text{mgh}\]and         \[\text{mgh}=\text{4}0\times \text{9}.\text{8}\times \text{h}\] Now,        \[P(A'\cap B')=1-P(A\cup B)=\frac{1}{3}\] \[|e|=\frac{d\phi }{dt}=B\frac{dA}{dt}\]              \[[\because \phi =BA]\] \[=\pi B\frac{d}{dt}({{r}^{2}})\]\[|e|=\pi B.2r\frac{dr}{dt}\] \[\frac{dr}{dt}={{10}^{-2}}\]        \[\text{B}=\text{1}{{0}^{-\text{3}}}\] \[e=1\mu V\]    \[\therefore \]                        


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