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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2014

  • question_answer
    The origin is shifted to (1, 2). The equation \[\text{1}.\text{96}\times \text{1}{{0}^{-\text{8}}}\text{ m}/\text{s}\] changes to \[\text{2}.\text{12}\times \text{1}{{0}^{\text{8}}}\text{ m}/\text{s}\] Then, \[\text{3}.\text{18}\times \text{1}{{0}^{8}}m/s\] is equal to

    A)  1                            

    B) 2 

    C)  -2                                          

    D) -1

    Correct Answer: B

    Solution :

                    Let P(x, y) be the original position of the point with respect to the original axes. Let us move the origin at new position (h, k). Hence, the position of the same point P in the new system is \[\frac{B}{4}\] Here,     \[\frac{B}{2}\] \[y=A\sin (Bx+Ct+D)\]   \[[{{m}^{0}}{{L}^{-1}}{{T}^{0}}]\] According to the question, \[[{{m}^{0}}{{L}^{0}}{{T}^{-1}}]\] \[[{{m}^{0}}{{L}^{-1}}{{T}^{-2}}]\]\[[{{m}^{0}}{{L}^{0}}{{T}^{0}}]\] On comparing the coefficients of x. we get \[1.5\mu \]          


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