A) \[10\times {{10}^{3}}W\]
B) \[20\times {{10}^{3}}W\]
C) \[4\times {{10}^{3}}W\]
D) \[6\times {{10}^{3}}W\]
Correct Answer: A
Solution :
\[W=mgh=200\times {{g}_{0}}\times {{\tau }_{0}}\] \[=100000\text{ }J=100\text{ }kT\] \[P=\frac{100\times {{10}^{3}}}{10}=10\times {{10}^{3}}W\]
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