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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
        Two particles A and B of masses\[{{m}_{A}}\]and\[{{m}_{B}}\] respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The spead of the particles are\[{{\upsilon }_{A}}\]and\[{{\upsilon }_{B}}\]respectively and the trajectories are as shown in the figure. Then,

    A)  \[{{m}_{A}}{{v}_{A}}<{{m}_{B}}{{v}_{B}}\]         

    B)  \[{{m}_{A}}{{v}_{A}}>{{m}_{B}}{{v}_{B}}\]

    C)  \[{{m}_{A}}<{{m}_{B}}\,and\,{{v}_{A}}<{{v}_{B}}\]        

    D) \[{{m}_{A}}={{m}_{B}}\,and\,{{v}_{A}}={{v}_{B}}\]

    Correct Answer: B

    Solution :

                    Radius of the circle\[=\frac{mv}{qB}\] or radius\[\propto \]\[mv\]if B and q are same \[{{(radius)}_{A}}>{{(radius)}_{B}}\] \[\therefore \]  \[{{m}_{A}}{{v}_{A}}>{{m}_{B}}{{v}_{B}}\]


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