A) 300 min
B) 360 min
C) 398.8mm
D) 400 min
Correct Answer: C
Solution :
For first order reaction, \[t=\frac{2.303}{k}\log \frac{a}{a-x}\] For 1st case, \[a=100,\text{ }x=50\text{ }and\text{ }t=120\text{ }min\] \[k=\frac{2.303}{120}\log \frac{100}{100-50}\] \[=\frac{2.303}{120}\log 2\] \[=\frac{2.303}{120}\times 0.3010\] \[k=0.005775{{\min }^{-1}}\] For the Und case \[t=\frac{2.303}{0.005775}\log \frac{100}{100-90}\] \[=\frac{2.303}{0.005775}\log 10\] \[=398.78-398.8\text{ }min\]
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