A) 0.81 kWh
B) 0.90 kWh
C) 1.11 kWh
D) 0.71 kWh
Correct Answer: A
Solution :
\[1\text{ }kcal={{10}^{3}}cal\] \[4200\text{ }J=\frac{4200}{3.6\times {{10}^{8}}}kWh\] \[700\,kcal=\frac{700\times 4200}{3.6\times {{10}^{6}}}kWh\] \[=0.81\text{ }kWh\]
You need to login to perform this action.
You will be redirected in
3 sec
