A) \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,HC{{H}_{3}}\]
B) \[C{{H}_{3}}\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,C{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\]
D) \[C{{H}_{3}}C{{H}_{2}}\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: D
Solution :
The alcohols having the structure\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-\] or ketones having the unit\[C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,H-\]give iodoform test. \[C{{H}_{3}}C{{H}_{2}}COC{{H}_{2}}C{{H}_{3}}\]does not have such kind of structure, hence it will not give iodoform test.
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