A) 10cm
B) \[10\sqrt{2}cm\]
C) 20cm
D) \[5\sqrt{2}cm\]
Correct Answer: D
Solution :
\[r=\frac{1}{B}\sqrt{\frac{2mv}{2}}\] \[\frac{{{r}_{\alpha }}}{{{\gamma }_{p}}}=\sqrt{\frac{{{m}_{\alpha }}}{{{m}_{p}}}}\sqrt{\frac{{{q}_{p}}}{{{q}_{\alpha }}}}\] \[\therefore \] \[\frac{{{r}_{\alpha }}}{10}=\sqrt{\frac{4}{2}}\] \[{{r}_{2}}=10\sqrt{2}\,cm\]
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