JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2009

  • question_answer
        The transfer ratio\[\beta \]of a transistor is 50. The input resistance of the transistor when used in the common emitter mode is\[1\,k\Omega \]. The peak value of the collector alternating current for an input peak voltage of 0.01 V is

    A)  \[100\text{ }\mu A\]                                    

    B)  \[\text{500 }\mu A\]

    C)  \[\text{0}\text{.01 }\mu A\]                     

    D)  \[\text{0}\text{.25 }\mu A\]

    Correct Answer: B

    Solution :

                    Input current \[=\frac{{{V}_{i}}}{{{R}_{i}}}=\frac{0.01}{{{10}^{3}}}A\] \[={{10}^{-5}}A\] Output collector current                 \[{{i}_{c}}={{\beta }_{iB}}=50\times {{10}^{-5}}A\]                 \[{{i}_{c}}=50\,\mu A\]


You need to login to perform this action.
You will be redirected in 3 sec spinner