A) \[6.6\times {{10}^{-20}}kg\text{ }m{{s}^{-1}}\]
B) \[3.3\times {{10}^{-20}}kg\text{ }m{{s}^{-1}}\]
C) \[3.3\times {{10}^{-48}}kg\text{ }m{{s}^{-1}}\]
D) \[6.6\times {{10}^{-48}}kg\text{ }m{{s}^{-1}}\]
Correct Answer: B
Solution :
Since \[\Delta x:\Delta p=h\] \[\therefore \] \[2\times 10-14\times \Delta p=6.6\times {{10}^{-34}}\] \[\Rightarrow \] \[\Delta p=\frac{6.6\times {{10}^{-34}}}{2\times {{10}^{-14}}}\] \[\Rightarrow \] \[\Delta p=3.3\times {{10}^{-20}}kg\,m{{s}^{-1}}\]
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