A) \[{{H}_{2}}PO_{2}^{-}\]
B) \[HPO_{3}^{2-}\]
C) \[HPO_{4}^{2-}\]
D) all of the above
Correct Answer: C
Solution :
\[HPO_{4}^{2-}+{{H}_{2}}O{{H}_{2}}PO_{4}^{2-}+O{{H}^{-}}\] \[HPO_{4}^{2-}+{{H}_{2}}OPO_{4}^{3-}+{{H}_{3}}{{O}^{+}}\] \[{{H}_{2}}PO_{2}^{-}\]is a conjugate base of\[{{H}_{3}}P{{O}_{2}}\](a monobasic acid and does not give\[{{H}^{+}}\]\[HPO_{3}^{2-}\] is a conjugate base of\[{{H}_{2}}PO_{3}^{-}\]and does not ionise further since\[{{H}_{3}}P{{O}_{3}}\]is a dibasic acid.
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