A) \[{{F}_{2}}+2{{e}^{-}}\xrightarrow[{}]{{}}2{{F}^{-}}\]
B) \[2{{H}^{+}}+\frac{1}{2}{{O}_{2}}+2{{e}^{-}}\xrightarrow[{}]{{}}{{H}_{2}}O\]
C) \[2Cr_{2}^{3+}+7{{H}_{2}}O\xrightarrow[{}]{{}}C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\]
D) \[F{{e}^{2+}}\xrightarrow[{}]{{}}F{{e}^{3+}}+{{e}^{-}}\]
Correct Answer: D
Solution :
Oxidation takes place at anode.
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