JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        Three   straight   lines\[2x+11y-5=0,\] \[24x+7y-20=0\]and\[4x-3y-2=0\]:

    A)  form a triangle

    B)  arc only concurrent

    C)  are concurrent with on line bisecting the angle between the other two

    D)  none of these

    Correct Answer: C

    Solution :

                     For the two lines\[24x+7y-20=0\]and\[4x-3y-2=0,\]the angle bisectors are given by \[\frac{24x+7y-20}{25}=\pm \frac{4x-3y-2}{5}\] Taking positive sign, we get \[2x+11y-5=0\]therefore the given three lines are concurred with on line bisecting the angle between the other two.


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