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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        Tube A has both ends open while tube B has one end closed, otherwise they are identical. The ratio of fundamental frequency of tubes A and B is:

    A)  \[1:2\]                                 

    B)  \[1:4\]

    C) \[2:1\]                                  

    D)  \[4:1\]

    Correct Answer: C

    Solution :

                    Let the tubes A and B have equal length called as\[l\]. Since, tube A is opened at both the ends, therefore, its fundamental frequency \[{{n}_{A}}=\frac{v}{2l}\]                                           ...(1) Since, tube B is closed at one end, therefore, its fundamental frequency \[{{n}_{B}}=\frac{v}{4l}\]                                ...(2) From eqs. (1) and (2), we get                 \[\frac{{{n}_{A}}}{{{n}_{B}}}=\frac{\frac{v}{2l}}{\frac{v}{4l}}\]                 \[=\frac{4}{2}=2:1\]


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