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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        Energy of H-atom in the ground state is\[-13.6\] eV, hence energy in the second excited state is:

    A)  \[-6.8eV\]                         

    B)  \[-3.4eV\]

    C)  \[-1.51eV\]                       

    D)  \[-4.53eV\]

    Correct Answer: C

    Solution :

                    \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\] For second excited state\[n=3,\]                 \[{{E}_{3}}=-\frac{13.6}{9}=-1.51\,eV\]


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