A) \[C{{H}_{3}}Br+Na\to \]
B) \[C{{H}_{3}}CHO\xrightarrow{HCN}A\xrightarrow{HOH}B\]
C) \[\text{Pb}+\text{Zn}+\text{Sn}\]
D) \[\text{Pb}+\text{Zn}\]
Correct Answer: A
Solution :
\[\underset{5\,mol/litere}{\mathop{A{{s}_{2}}{{S}_{3}}}}\,\underset{2s}{\mathop{2A{{s}^{3+}}}}\,+\underset{3s}{\mathop{3{{S}^{2-}}}}\,\] \[\therefore \] \[{{K}_{sp}}={{[A{{s}^{3+}}]}^{2}}{{[{{S}^{2-}}]}^{3}}\] \[={{(2s)}^{2}}{{(3s)}^{3}}\] \[=108{{s}^{5}}\] \[\therefore \] \[s=\sqrt[5]{\frac{{{K}_{sp}}}{108}}\,or\,{{\left( \frac{{{K}_{sp}}}{108} \right)}^{\frac{1}{5}}}\] \[=\sqrt[5]{\frac{2.8\times {{10}^{-72}}}{108}}\] \[=\sqrt[5]{25.93\times {{10}^{-75}}}\] \[=1.92\times {{10}^{-15}}mole/litre\]
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