A) 0.25 m
B) 0.5 m
C) 0.75 m
D) zero
Correct Answer: D
Solution :
Displacement in the -nth second is given by \[{{S}_{n}}=4+\frac{a}{2}(2n-1)\] In this problem retardation is involved. Thus, the equation becomes \[{{S}_{n}}=4-\frac{a}{2}(2n-1)\] Given \[u=9\text{ }m/s,\text{ }a=2\text{ }m/s\] \[n=5\] \[\Rightarrow \] \[{{S}_{5}}=-\frac{2}{2}(2\times 5-1)\] \[=9-9=0\]
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