A) 0.001 cm
B) 0.002cm
C) 0.01 cm
D) 0.02cm
Correct Answer: B
Solution :
Least count of vernier calliper \[LC=1\,MSD-1\,VSD\] where, MSD = Main Scale Division VSD = Vernier Scale Division \[=0.5\,mm-\frac{24}{25}MSD\] \[=0.5\,mm-\frac{24}{25}\times 0.5mm\] \[=0.5\,m\left( 1-\frac{24}{25} \right)=0.5mm\times \frac{1}{25}\] \[=\frac{1}{50}mm=0.02mm=0.002\,cm\]
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