A) \[6.023\times {{10}^{23}}\]
B) 2
C) 1
D) \[12.046\times {{10}^{23}}\]
Correct Answer: D
Solution :
\[\because \]23 g of Na contains\[=6.023\times {{10}^{23}}\]atoms \[\therefore \]1 g of Na contains\[=\frac{6.023\times {{10}^{23}}}{23}atoms\] \[\therefore \]46 g of Na contains\[=\frac{6.023\times {{10}^{23}}}{23}\times 46\,atoms\] \[=12.046\times {{10}^{23}}atoms\]
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