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J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    The ratio of magnitude of electric displacement  and electric field  is

    A)  charge density

    B)  permittivity

    C)  electric susceptibility

    D)  dielectric constant

    Correct Answer: B

    Solution :

     The dimension of electric displacement D = [Dimension of £o] [Dimension of E] So,            \[\frac{[D]}{[E]}=\frac{[{{\varepsilon }_{0}}][E]}{[E]}=[{{\varepsilon }_{0}}]\] So, \[\frac{D}{E}=Permitivity\]


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