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J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    An athlete throws the shot-put of mass 4 kg with initial speed of\[2.2\text{ }m{{s}^{-1}}\]at\[41{}^\circ \]from a height of 1.3 m from the ground. What is the KE of the shot-put when it reaches the ground? (Ignoring the air resistance and gravity \[g=9.8m/{{s}^{2}}\])

    A)  42.84 J            

    B)  52.84 J

    C)  62.84 J            

    D)  72.84 J

    Correct Answer: C

    Solution :

     As there is no air resistance and gravitational force is a conservative force, we can apply mechanical energy conservation. \[\Rightarrow \] \[{{(KE)}_{f}}={{(KE)}_{i}}+Change\text{ }in\text{ }PE\] \[=\frac{1}{2}m{{v}^{2}}+mgh\] \[=\frac{1}{2}\times 4\times {{(2.2)}^{2}}+4\times (9.8)\times (1.3)\] \[=9.68+50.96\] \[=60.64\approx 62.84J\]


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