A) \[2\times {{10}^{-4}}Wb/{{m}^{2}}\]
B) \[3\times {{10}^{-5}}Wb/{{m}^{2}}\]
C) \[4\times {{10}^{-4}}Wb/{{m}^{2}}\]
D) \[4\times {{10}^{-5}}Wb/{{m}^{2}}\]
Correct Answer: B
Solution :
Magnetic field\[B=\frac{{{\mu }_{0}}I}{2\pi r}\] Given, \[\mu =4\pi \times {{10}^{-7}}N/{{A}^{2}},\] \[r=8cm=8\times {{10}^{-2}}m\] \[I=12A\] \[B=\frac{4\pi \times {{10}^{-7}}}{2\pi }\times \frac{2}{8\times {{10}^{-2}}}\] \[\Rightarrow \] \[B=3\times {{10}^{-5}}Wb/{{m}^{2}}\]
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