A) 1-propanol
B) 2-propanol
C) ethanol
D) butanol
Correct Answer: A
Solution :
\[\underset{propanal}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,+LiAl{{H}_{4}}/{{H}_{2}}O\xrightarrow[{}]{{}}\underset{1-propanol}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,\]
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