J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    The decreasing order of acidity among the compounds,  
     ethanol (I) 
     2, 2, 2-trifluoroethanol (II),
     trifluroacetic acid (III) 
     and acetic acid (IV)
     is
     

    A)  \[III\text{ }>\text{ }II\text{ }>\text{ }IV\text{ }>\text{ }I\]

    B)  \[IV\text{ }>\text{ }III\text{ }>\text{ }II\text{ }>\text{ }I\]

    C)  \[I\text{ }>\text{ }II\text{ }>\text{ }III\text{ }>\text{ }IV\]

    D)  \[III\text{ }>\text{ }IV\text{ }>\text{ }II\text{ }>\text{ }I\]

    Correct Answer: A

    Solution :

    The acidic character increases with increasing number of electron withdrawing substituents on the a-carbon. Hence, trifluoroacetic acid is more acidic than acetic acid. Further carboxylic acids are more stronger acid than alcohols but due to the presence of three electron withdrawing group (\[F\]group), 2, 2, 2, trifluoroethanol is more acidic than acetic acid.


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