A) 4
B) 6
C) 8
D) 12
Correct Answer: A
Solution :
Zinc blende\[(ZnS)\]has fee structure. It is anionic crystal having\[4:4\]coordination number.\[{{S}^{2-}}\]form fee lattice and\[Z{{n}^{2+}}\]has alternate tetrahedral voids. Hence, in zinc blende structure, the coordination number of cation\[(Z{{n}^{2+}})\]is 4.You need to login to perform this action.
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