A) \[-\,11\]
B) \[-\,44\]
C) \[-\,55\]
D) \[-\,22\]
Correct Answer: C
Solution :
Heat of neutralisation is the heat that evolved when one equivalent of acid is neutralised by one equivalent of a base. \[\because \] Mill equivalents of weak acid\[=400\times 0.2\] = 80 mill equivalents \[\therefore \]Equivalents of the acid = 0.08 equivalent. Since, heat evolved when 0.08 equivalent of acid is neutralized = 4.4 kJ \[\therefore \]The heat evolved, when 1 equivalent is neutralised \[=\frac{4.4\times 1}{0.08}\] \[=55\,kJequi{{v}^{-1}}.\]
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