A) \[B<D<A<C\]
B) \[C<A<D<B\]
C) \[D<B<C<A\]
D) \[A<C<D<B\]
Correct Answer: B
Solution :
Lower the value of standard enthalpy of formation, higher the stability. The increasing order of standard enthalpies of formation of given molecules is \[\underset{B(C{{O}_{2}})}{\mathop{393.4}}\,<\underset{D(S{{O}_{2}})}{\mathop{296.9}}\,<\underset{A(N{{H}_{3}})}{\mathop{-46.19}}\,<\underset{C(HI)}{\mathop{+24.94}}\,\] Thus, the increasing order of stability is \[C\text{ }<\text{ }A\text{ }<\text{ }D\text{ }<\text{ }B\]
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