A) U, 92 and 235
B) Th, 90 and 232
C) Pu, 94 and 238
D) U, 92 and 238
Correct Answer: D
Solution :
The given radioactive decay can be written in the following manner: \[_{y}{{X}^{z}}{{\xrightarrow[{}]{{}}}_{82}}P{{b}^{206}}+{{8}_{2}}H{{e}^{4}}+{{6}_{-1}}{{\beta }^{o}}\] On comparing, \[z=206+8\times 4+6\times 0\] \[z=238\] \[y=82+8\times 2-1\times 6\] \[=82+16-6=92\] Atomic number of uranium (U) is 92, so X is U.
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