2. Solved Papers
  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    The set of quantum numbers\[n=4,l=0\text{ }m=0\] and\[s=+\frac{1}{2}\]correspond to the most loosely bound, ground state electron of which one of the following atoms?

    A)  Na                                        

    B) \[Cl\]

    C)  Cr                                          

    D) \[Rb\]

    Correct Answer: C

    Solution :

                    \[n=4,l=0,m=0\]and\[s=+\frac{1}{2}\]set represents that the last electron enters in a 45 orbital. Among the given options, only Cr is the element, last electron of which enters in a 4s orbital. \[Cr=[Ar]\text{ }3{{d}^{5}},\text{ }4{{s}^{1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner