J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    If the de-Broglie wavelength of a particle of mass m is 100 times its velocity then its value in terms of its mass (m) and Plancks constant (h) is

    A)  \[\frac{1}{10}\sqrt{m/h}\]                         

    B)  \[10\sqrt{h/m}\]

    C)  \[\frac{1}{10}\sqrt{h/m}\]                         

    D)  \[10\sqrt{m/h}\]

    Correct Answer: B

    Solution :

                    Let the velocity of the particle\[=v\] \[\therefore \]Wavelength\[(\lambda )\]of the particle\[=100\text{ }v\] or      \[v=\frac{\lambda }{100}\] de-Broglie relationship is \[\lambda =\frac{h}{m.v}\] or        \[\lambda =\frac{h\times 100}{m.\lambda }\] or            \[{{\lambda }^{2}}=\frac{h\times 100}{m}\]                 \[\lambda =10\sqrt{\frac{h}{m}}\]


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