J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    The number of molecules in 18 mg of water in terms of Avogadro number N is

    A)  \[{{10}^{-3}}N\]                              

    B) \[{{10}^{-2}}N\]

    C)  \[{{10}^{-1}}N\]                              

    D) \[10N\]

    Correct Answer: A

    Solution :

                    Given, weight of water\[=18\text{ }mg=18\times {{10}^{-3}}g\] \[\therefore \] Number of moles\[=\frac{weight}{molar\,mass}\]                                 \[=\frac{18\times {{10}^{-3}}}{18}=1\times {{10}^{-3}}\] and number of molecules = no. of moles\[\times \] Avogadro number. \[=1\times {{10}^{-3}}\times N\] \[={{10}^{-3}}N\]


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