A) \[\frac{molar\,mass}{5}\]
B) \[\frac{molar\,mass}{3}\]
C) \[\frac{molar\,mass}{2}\]
D) molar mass itself
Correct Answer: D
Solution :
In alkaline medium, \[\overset{+7}{\mathop{2KMn{{O}_{4}}}}\,+2KOH\xrightarrow[{}]{{}}\overset{+6}{\mathop{2{{K}_{2}}Mm{{O}_{4}}}}\,+{{H}_{2}}O+[O]\] Change in oxidation state of \[Mn=(+7)-(+6)\] \[=+1\] \[\therefore \]Eq. wt. of \[KMn{{O}_{4}}=\frac{molar\text{ }mass}{change\text{ }in\text{ }oxidation\text{ }state}\] \[=\frac{molar\text{ }mass}{1}=\] molar mass
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