A) twice the audio signal frequency
B) thrice the audio signal frequency
C) thrice the carrier wave frequency
D) twice the carrier wave frequency
Correct Answer: A
Solution :
In an AM wave, the bandwidth is from\[({{f}_{c}}-{{f}_{m}})\]to\[({{f}_{c}}+{{f}_{m}})\]ie,\[2{{f}_{m}}\]which is twice the signal frequency\[({{f}_{m}})[{{f}_{c}}\]is the carrier frequency].You need to login to perform this action.
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