A) 2 : 1
B) 1 : 2
C) \[\sqrt{2}:1\]
D) \[\sqrt{3}:1\]
Correct Answer: C
Solution :
de-Broglie wavelength\[\lambda =\frac{h}{\sqrt{2mE}}\] or \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\] [As h is constant and E is same for both the masses] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\sqrt{\frac{2}{1}}\] \[\Rightarrow \] \[{{\lambda }_{1}}:{{\lambda }_{2}}=\sqrt{2}:1\]
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