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J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    If the photoelectric work function for a metallic surface is 4.125 eV, the cut-off wavelength for photoelectric phenomenon for the surface is

    A)  4500\[\overset{0}{\mathop{A}}\,\]                       

    B)  1700 \[\overset{0}{\mathop{A}}\,\]

    C)  2800 \[\overset{0}{\mathop{A}}\,\]                      

    D)  3000 \[\overset{0}{\mathop{A}}\,\]

    Correct Answer: D

    Solution :

                     As        \[E(eV)=\frac{12375}{\lambda ({\AA})}\] \[4.125=\frac{12375}{\lambda }\] \[\lambda =\frac{12375}{4.125}\] \[=3000{\AA}\]


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