A) 100 m
B) 25 m
C) 200 m
D) 75 m
Correct Answer: B
Solution :
\[{{R}_{\max }}=\frac{{{u}^{2}}}{g}=100m\] The range of the projectile is maximum for the angle of projection\[\theta =45{}^\circ \]. When the range is maximum the height attained by a projectile is, \[H=\frac{{{u}^{2}}}{4g}=\frac{100}{4}=25\,m\]You need to login to perform this action.
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