J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    The average power dissipated in a pure capacitance AC circuit is

    A)  CV                                        

    B)  zero

    C) \[\frac{1}{C{{V}^{2}}}\]                                

    D) \[\frac{1}{4}C{{V}^{2}}\]

    Correct Answer: B

    Solution :

                     Average power in AC circuit is given by \[P={{V}_{rms}}{{I}_{rms}}\cos \phi \] For pure capacitive circuit\[\phi ={{90}^{o}}\]so\[P=0\]


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