question_answer

A uniformly wound coil of self-inductance \[1.2\times {{10}^{-4}}H\] and resistance 3\[\Omega \] is broken up into two identical coils. These coils are then connected parallely across a 6V battery of negligible resistance. The time constant for the current in the circuit is (neglect mutual inductance)

A) \[0.4\times {{10}^{-\text{ }4}}s\]                             

B)  \[0.2\times {{10}^{-\text{ }4}}s\]

C) \[0.5\times {{10}^{-4}}s\]                            

D)  \[0.1\times {{10}^{-4}}s\]